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Mathematics

1 answer:

mars1129 [50]3 years ago

7 0

Answer:

Step-by-step explanation:

the circumference of the circle, C=2*3.14*r

C=3.14*d

C=3.14*12=37.68

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Brittanya opened a savings account with $200. She saves $50 per month. Which of the following equations can be used to find how

monitta

50x12=600 600+200=800

4 0

3 years ago

Determine the t critical value for a lower or an upper confidence bound in each of the following situations. (Round your answers

Vinvika [58]

Answer:

A. 1.812

B. 1.753

C. 2.602

D. 3.747

E. 2.069

F. 2.453

Step-by-step explanation:

A. 95% confidence level, the level of significance = 5% or 0.05

Using t-table, the critical value for a lower or an upper confidence bound at 0.05 significance level with 10 degrees of freedom = 1.182

B. 95% confidence interval = 0.05 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.05 significance level with 15 degrees of freedom = 1.753

C. 99% confidence interval = 0.01 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 15 degrees of freedom = 2.602

D. 99% confidence interval = 0.01 level of significance; DF (n - 1) = 5- 1 = 4

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 4 degrees of freedom = 3.747

E. 98% confidence interval = 0.02 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.02 significance level with 23 degrees of freedom = 2.069

F. 99% confidence interval = 0.01 level of significance; df (n - 1) = 32 - 1 = 31

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 31 degrees of freedom = 2.453

7 0

4 years ago

Given: KLMN is a trapezoid, m∠N=m∠KML, FD=8, LM/KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3sqrt5 Find: KM

den301095 [7]

Answer:

KM = √70 ≈ 8.367

Step-by-step explanation:

FD is a midsegment whose length (8) corresponds to the average of the numbers of ratio units of LM : KN = 3 : 5. That is, each of those ratio units must be 2 length units, so KN = 10.

∠MKN = ∠KML = ∠N because the first two angles are alternate interior angles where transversal MK crosses parallel lines ML and KN. The latter two of these angles are equal because the problem statement says so.

These angle relationships make ΔKMN an isosceles triangle, with E the midpoint of the base. That is, KE = 5. We are told ME = 3√5, so the Pythagorean theorem tells us ...

... KM² = KE² +ME² = 5² +(3√5)² = 70

... KM = √70 . . . . . take the square root