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Mademuasel [1]
3 years ago
7

During the course of execution of a program, the processor will increment the contents of the instruction register (program coun

ter) by one word after each instruction fetch, but will alter the contents of that register if it encounters a branch or call instruction that causes execution to continue elsewhere in the program. There are two alternatives with respect to instruction addresses:
a. Maintain a relative address in the instruction register and do the dynamic address translation using the instruction register as input. When a successful branch or call is encountered, the relative address generated by that branch or call is loaded into the instruction register .
b. Maintain an absolute address in the instruction register. When a successful branch or call is encountered, dynamic address translation is employed, with the results stored in the instruction register
Computers and Technology
1 answer:
Oksana_A [137]3 years ago
8 0
Bdbdbdhdhdhdhdjdbsbbrvrvrrvrvrvfvfvvfvfvfvfvfhdhdhdhdhdhdhhdududududududuebebbedvdvd I known why ahh it happened
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Write a program that produces this output:
AveGali [126]

Answer:

void printC()  

{  

   int i, j;  

   for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows

       {  

         printf("C"); //print C for every row  

         for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows

         {  

           if (i == 0 || i == 4) //For first and last row  

               printf("C"); //print 'CCCCCCC'

          else if (i = 1|| i= 3) //for Second forth row  

                printf("C        +      +"); //print 'C    +    +'

          else if (i = 2) For second row  

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           else

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         }  

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}  

}

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Explanation:

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Programming CRe-type the code and fix any errors. The code should convert non-positive numbers to 1.
LUCKY_DIMON [66]

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Download cpp
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