Nelson is selling his photographs at an art festival the festival is open for 6 hours each day for 3 days at the conclusion of t
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Expanding the digits, we have
Hey there!
By using this formula, we plug it in.
Your correct answer would be . . .
≈ 
Hope this helps.
~Jurgen
By using this formula, we plug it in.
Your correct answer would be . . .
Hope this helps.
~Jurgen
Synthetic division yields
..... || 2 2 -12 1 6
-3 || -6 12 0 -3
= = = = = = = = = = = = = =
..... || 2 -4 0 1 3
which translates to
The given exponential function can be used to determine the
population of the fish at different times.
Response:
1. 200
2. 0.05
3. Please find attached the graph of the exponential function and the table
4. Range; [0, ∞)
Domain: [200, ∞)
5. 346 fishes (approximate value)
<h3>How is the population of the fish obtained from the exponential function?</h3>The given function is f(x) = 200·(1.05)ˣ
1. The initial population is given by the value of the function when x = 0,
which is given as follows;
At x = 0, f(0) = 200·(1.05)⁰ = 200
- The initial population of the fish is <u>200</u>
2. The rate of growth of the fish from the exponential function is given as follows;
The growth factor = 1.05
- The growth rate =<u> 0.05</u>
3. Please find attached the graph of the exponential function created
with MS Excel.
The asymptote of the exponential function is the line, <u>y = 0</u>
The table of values is presented as follows;
4. The domain is the possible x-values which is; 0 ≤ x < ∞
The range is the possible y-values which is; 200 ≤ f(x) < ∞
Which gives;
- Domain; [0, ∞)
- Range: [200, ∞)
5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹
f(11) = 200 × (1.05)¹¹ ≈ 342
- The population of the fish after 11 years is <u>346 (fishes)</u>
Learn more about exponential function here:
