H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
Answer:
21
Step-by-step explanation:
21212121212121213121212
Answer:
The standard error of the mean would be 6.5556.
Step-by-step explanation:
The standard error of the mean is given by the following formula:
In which n is the size of the sample and is the standard deviation of the population.
In this problem, we have that:
If a sample of 324 students are given the test, what would be the standard error of the mean?
The standard error of the mean would be 6.5556.
I believe it’s C. Have a good day. Hope this helps.