Answer: 20+44=64
32+56=88
88+64=$152
Step-by-step explanation:
Answer:
The answer is B or 8
Step-by-step explanation:
<h3>Answers are:
sine, tangent, cosecant, cotangent</h3>
Explanation:
On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.
Since sine is negative, so is cosecant as this is the reciprocal of sine
csc = 1/sin
In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.
Because tangent is negative, so is cotangent.
The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.
Answer:

Step-by-step explanation:
The hyperbola has x-intercepts, so it has a horizontal transverse axis.
The standard form of the equation of a hyperbola with a horizontal transverse axis is 
The center is at (h,k).
The distance between the vertices is 2a.
The equations of the asymptotes are
1. Calculate h and k. The hyperbola is symmetric about the origin, so
h = 0 and k = 0
2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6
a = 6/2 = 3
3. For 'b': The equation for the asymptote with the positive slope is

Thus, asymptote has the slope of

4. The equation of the hyperbola is

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.
Answer:20
Step-by-step explanation:
because you are finding out the base so width times length