1 1/3+2 3/4 simplified
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Answer:
(0.059, 0.133)
Step-by-step explanation:
Sample size = n = 250
Number of units which failed the test = x = 24
Proportion of units which failed the test = = 0.096
Proportion of units which did not fail the test = q = 1 - p = 1 - 0.096 = 0.904
Confidence level = 95%
z-value for the confidence level = z = 1.96
The true proportion of the components that fail to meet the specification would be:
Using the values, we get:
Thus, 95% confidence interval estimate for the true proportion of components, p, that fail to meet the specifications is (0.059, 0.133)