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Eva8 [605]
3 years ago
13

Kinda ez please help aced+

Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

Step-by-step explanation:

really need these points im sorry good luck tho

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The recycling bin in the shape of a rectangular prism is 15.5 inches long, 8 inches wide and 7 inches high. The recycling bins n
Viktor [21]

Answer:

694 cubic inches

Step-by-step explanation:

Dimension of prism

Length = 15.5 inches

width =  8 inches

height =  7 inches

Volume of regular prism is given  by area of base * height

area of base  = length * width ( as bin is rectangular)

area of base  = 15.5 * 8 square inches = 124 square inches

Volume of regular prism = area of base * height

      = 124 * 7 cubic inches = 868 cubic inches

_________________________________________________

868 cubic inches is the full capacity of the recycling bin

it is given that recycling bins need to be emptied when it is 80% full

so we need to find the 80% capacity of recycling bin

80% capacity of recycling bin = 80/100 *  full capacity of the recycling bin

                  = 0.8 * 868 cubic inches = 694.4 cubic inches

694.4 cubic inches is the amount needed before the recycle bin is ready to empty .

But question says answer should in nearest cubic inch

hence answer is 694 cubic inches

3 0
3 years ago
Can somebody please help me with this question??<br>10=10(k-9)
SashulF [63]
K = 10

I think. I’m not positive sure though. Hope this helped!
4 0
3 years ago
Read 2 more answers
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
I need help :p......​
IRISSAK [1]

Answer:

I believe the answer is C

Step-by-step explanation:

3 0
3 years ago
Destiny has 10$ and Elijah has 5$. I give each person the same amount of money each week. This situation can be represented with
Darina [25.2K]

Answer:

I do believe that the answer is 0 solutions.

Step-by-step explanation:

x+10 =x+5

Subtract 5 from both sides, you get:

x+5=x

Subtract x from both sides, and you get:

5=0 which is NOT true. Also I maybe wrong, pls don't be mad at me.

8 0
2 years ago
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