3 years ago

Why would we start at (0,200)?

Mathematics

1 answer:

DedPeter [7]3 years ago

7 0

Answer:

Look below.

Step-by-step explanation:

It starts at (0, 200) because Mr. Sullivan originally started with $200.

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Find (x - 6)2

Sever21 [200]

Its 4-6=2 its easy because just keep useing numbers until the become two

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3 years ago

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Factor the expression using the GCF 21+15

Svet_ta [14]

Answer:

3(7+5)

Step-by-step explanation:

21+15

Each term is divisible by 3

3*7 +3*5

3(7+5)

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4 years ago

What is the answer to this question because i do not know 5/12 x =1

Otrada [13]

Answer:

x=12/5

Step-by-step explanation:

x*5/12=1

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2 years ago

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A set of furniture was sold for GH cedis 3000 at a profit of 25%. Find the cost price.

Sindrei [870]

Answer:

<h2>2400GH Cedis </h2>

Step-by-step explanation:

$Selling \:price = 3000gh Cedis\\Profit \% = 25\%\\Cost\:price =?\\\\CP =\frac{ ( Selling\:price \times 100 )}{ ( 100 + percentage profit)} \\\\C.P = \frac{3000\times 100 }{100+25}\\\\ C.P = \frac{300000}{125} \\\\Cost\: Price = 2400gh Cedis$

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3 years ago

The ice cream shop offers 31 flavors. you order a double scoop cone how many different ways can the clerk put the ice cream on t

Lynna [10]

Answer:

465

Step-by-step explanation:

Since we are looking for the the number of combinations to have 2 different flavors in the ice cream, we can use the formula for combination.

$_{n}C_{k}=\dfrac{n!}{k!(n-k)!}$

Our variables are:

n = 31

k = 2

$_{31}C_{2}=\dfrac{31!}{2!(31-2)!}$

$_{31}C_{2}=\dfrac{31!}{2!29!}$

$_{31}C_{2}=465$

The number of possible combinations of having 2 different flavors out of 31 different flavors is 465.

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3 years ago