Question

Please help me to get its HCF​

Answer 1

Answer:

x²+x+1

Step-by-step explanation:

1st one,

x³-1

= (x-1)(x²+x+1)

2nd one,

x⁴+x²+1

= x⁴+x³-x³+x²+x²-x²+1+x-x

= x⁴+x³+x²-x³-x²-x+x+x²+1

= x²(x²+x+1)-x(x²+x+1)+(x²+x+1)

= (x²+x+1)(x²-x+1)

3rd one,

x³+1+2x²+2x

= x³+x²+x²+x+x+1

= x³+x²+x+x²+x+1

= x(x²+x+1)+(x²+x+1)

= (x²+x+1)(x+1)

So, here the common part among these three is,

x²+x+1, so it's the H.C.F.