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Alika [10]
3 years ago
15

Two supporting reasons are missing from the proof. Complete the proof by dragging and dropping the appropriate reasons into each

of the empty boxes.
Given: m∥n m∠3=120°

Prove: m∠8=60° 

Statements         Reasons
​ m∥nm∠3=120° ​ Given
∠5≅∠3 __________
m∠5=m∠3 Angle Congruence Postulate
m∠5=120° Substitution Property of Equality
m∠8+m∠5=180° Linear Pair Postulate
m∠8+120°=180° ___________
​ m∠8=60° ​ Subtraction Property of Equality 

Answer choices: 

1. Angle Addition Postulate

2. Alternate Interior Angles Theorem

3. Substitution Property of Equality

4. Alternate Exterior Angles Theorem

Mathematics
2 answers:
yaroslaw [1]3 years ago
5 0

Answer:

The reason for ∠5≅∠3 is Alternate Interior Angles Theorem and the reason for ∠8+120°=180° is Substitution Property of Equality.

Step-by-step explanation:

It is given that the lines m and n are parallel to each other. The measure of angle 3 is 120 degree.

From the figure it noticed that the p is a transversal line intersecting the lines m and n.

According to the Alternate Interior Angles Theorem, if a transversal line intersect two parallel lines then the alternate interior angles are same.

By Alternate Interior Angles Theorem

\angle 3\cong \angle 5

\angle 4\cong \angle 6

Therefore, the reason for ∠5≅∠3 is Alternate Interior Angles Theorem.

Since the measure of angle 3 is 120 degree.

\angle 5=120^{\circ}

The angle 5 and 8 lies on a straight line, so by Linear Pair Postulate,

\angle 8+\angle 5=180^{\circ}

Use Substitution Property of Equality and substitute \angle 5=120^{\circ}.

\angle 8+120^{\circ}=180^{\circ}

Using Subtraction Property of Equality

\angle 8=60^{\circ}

Therefore the reason for ∠8+120°=180° is Substitution Property of Equality.

aksik [14]3 years ago
3 0

The answer is alternate interior angles theorem and substitution property of equality.

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Find the centroid of the quarter of the unit circle lying in the third quadrant.
asambeis [7]

As you know that  Centroid is the point of any curve ,Starting from a line segment it's centroid is it's mid point,  want to say that centroid means the point where the curve is balanced such that if at that point if you put anything it will remain balanced in all directions, whether it is a one dimensional figure,two dimensional figure,or three dimensional figure.For a circle it's center is the Centroid.

Now  coming to your question

Centroid of the quarter of the unit circle lying in the third quadrant.

Circle being a two dimensional figure. The equation of circle is

x^2+y^2=1\\

Applying the rule of integration i.e from (-1,0) to (0,-1). i.e from x_{1}=-1 \text{ to }   x_{2} =0 \text{  and } y_{1}=0\text{ to } y_{2} =-1-----[∵ we have to find centroid of a circle lying in the third quadrant.]

x^2+ y^2=1\\y^2=1-x^2\\y=\sqrt{1-x^{2}}

Applying the formula of centroid i.e

\bar{x}=\frac{1}{A}\int_{a}^{b}xy\text{ dx }\\\bar{y}=\frac{1}{2A}\int_{a}^{b}y^{2}\text{ dx }\\ \text{ or }\\\bar{y}=\frac{1}{A}\int_{a}^{b}yx\text{ dy }

where A is the area of circle which is \pi r^{2}.

Area of unit circle=π

Area of Quadrant of a circle=π/4

\bar{x}=\frac{4}{\pi}\int_{-1}^{0}x\sqrt{1-x^2}\text{ dx }

put, (1-x²)=t

differentiating both sides

-2 x dx = dt

x dx= - (dt/2)

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\bar{x}=-\frac{4}{3\pi}\int_{0}^{1}\sqrt{t}\text{ dt }}

\bar{x}=-\frac{4}{3\pi}{ t ^ \frac{3}{2}}_{0}^{1}

x coordinate=  \bar{x}   =-\frac{4}{3\pi}

Now finding the y -cordinate by using the above formula

\bar{y}=\frac{2}{\pi }\int_{0}^{-1}y^{2}\text{ dx }

\bar{y}=\frac{2}{\pi}\int\limits^{-1}_{0} {1-x^2} \, dx

\bar{y}=\frac{2}{\pi }[x-\frac{x^3}{3}]_{0}^{-1}

\bar{y}=-\frac{4}{3\pi}\\centroid(-\frac{4}{3\pi},-\frac{4}{3\pi})













5 0
4 years ago
A bagel shop sold 8 plain bagels and 13 rye bagels. What is the ratio of the number of rye bagels to the number of plain bagels
marshall27 [118]

Answer:

13 : 8

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13/8

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13 to 8

7 0
3 years ago
Quadrilateral A B C D is translated up and to the right and then is rotated 180 degrees about point Q to form quadrilateral X Y
pogonyaev

When a triangle is translated, the resulting triangle will be congruent to the original triangle.

The congruency statement is ABCD = ZYXW

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Quadrilateral ABCD is translated up and to the right and then is rotated 180 degrees about point Q to form quadrilateral XYZW.

Quadrilateral ABCD is translated up and to the right and then rotated about point Q.

<h3>What is translation?</h3>

When a triangle is translated, the resulting triangle will be congruent to the original triangle.

From the complete question, corresponding points are:

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Points A and Z are corresponding.

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6 0
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3 years ago
Do y’all the answer?
Strike441 [17]

Length = 12 m and width = \frac{7}{2} m.

Solution:

Let the width of the rectangle be w.

Length of the rectangle = 2w + 5

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$w=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 2(-42)}}{2 \cdot 2}

$w=\frac{-5 \pm \sqrt{25+336}}{4}

$w=\frac{-5 \pm \sqrt{361}}{4}

$w=\frac{-5 \pm19}{4}

$w=\frac{-5+19}{4}, w=\frac{-5-19}{4}

$w=\frac{14}{4}, w=\frac{-24}{4}

$w=\frac{7}{2}, w=-6

Dimension cannot be in negative, so neglect w = –6.

Width of the rectangle = \frac{7}{2} m

$L=2(\frac{7}{2} )+5=12 \  m

Hence length = 12 m and width = \frac{7}{2} m.

4 0
4 years ago
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