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stiks02 [169]
3 years ago
11

What is the solution of the system of equations shown in the graph below?

Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer:

Step-by-step explanation:

d

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What's the hcf and lcm of 5and 7​
svetlana [45]

Answer:

gcf, hcf, gcd (5; 7) = 1: greatest (highest) common factor (divisor), calculated. Coprime numbers (relatively prime). Numbers have no common prime factors.

7 0
3 years ago
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PLSSSS HELP IM SOOO BAD AT SIMPLIFYING FRACTIONS!!!!!!
pantera1 [17]

Answer:

A. 1/5

B. 1/2

C. 2/3

D. 3/5

E. 2/3

F. 3/8

G. 4/11

H. 3/7

I. 5/6

J. 4/11

K. 2/5

L. 1/4

Q. 27/36 = 3/4

Step-by-step explanation:

3 0
3 years ago
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Part A: Find the LCM of 7 and 12. Show your work. (3 points)
inna [77]

Answer:

A. 84; B. 8; C. 8 × 19

Step-by-step explanation:

Part A. Least common multiple

Step 1. List the prime factors of each.

7 = 7

12 = 2 × 2 × 3

Step 2: Multiply each factor the greatest number of times it occurs in either number.

7 has one 7; 12 has two 2s and one 3.

LCM = 7 × 2 × 2 × 3

LCM = 7 × 12

LCM = 84

Part B. Highest common factor

Find all the factors of 56 and 96.

Factors of 56: 1, 2, 4,     7, 8,      14,          28

Factors of 96: 1, 2, 4, 6,     8, 12,    16, 24,     32, 48

The highest factor that in both 56 and 96 is 8.

Part C. Factoring

56 + 96 = 8(7 + 12) = 8 × 19

The GCF is 8.

19 = 7 + 12 is the sum of two numbers that do not have a common factor.

4 0
4 years ago
PLZZZ HELPPPPPP!!!!!!!!!!! (STATISTICS)
V125BC [204]

Answer:

F

Step-by-step explanation:

F to pay respects

5 0
3 years ago
Line AB is tangent to circle O at A. The diagram is not drawn to scale.
Arlecino [84]
AO = 21
BC = 14
OC = radius of the circle = AO = 21
∴ OB = OC + CB = 21 + 14 = 35
<span>Line AB is tangent to circle O at A</span>
∴ AB is perpendicular to AO
∴ Δ OAB is a right triangle at A
Applying Pythagorean theorem
∴  OB² = AO² + AB²
∴ AB² = OB² - AO² = 35² - 21² = 1225 - 441 = 784
∴ AB = √784 = 28
<span />
8 0
4 years ago
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