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2 years ago

Which equation represents the line that passes through (-8,11) and

Mathematics

2 answers:

Nadusha1986 [10]2 years ago

5 0

Answer:

Option (A)

y = - 5 / 8 x + 6

Step-by-step explanation:

Two points are

(x', y') = ( - 8, 11 )

(x'', y'') = (4, 7/2)

The equation o line passing through two points is given by

$(y - y') = \frac{y'' - y'}{x''-x'}(x-x')\\\\(y - 11)= \frac{\frac{7}{2}-11}{4+8} (x + 8)\\\\y - 11 = \frac{-5}{8}(x + 8)\\\\y -11 = \frac{-5x}{8} - 5\\\\y = \frac{-5x}{8} + 6$

So, option (A) is correct.

Elena-2011 [213]2 years ago

4 0

Answer:

A) y = -5/8x + 6

Step-by-step explanation:

y2 - y`1 / x2 - x1

7/2 - 11 / 4 - (-8)

-15/2 / 12

= -5/8

y = -5/8x + b

11 = -5/8(-8) + b

11 = 5 + b

6 = b

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2 years ago

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Step-by-step explanation:

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Hope this helps you

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2 years ago

Where on the graph of 2x - 6y = 7 is the x-coordinate twice the y-coordinate?

Nikolay [14]

Answer:

The required point is P(-7, $\frac{-7}{2}$ ) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7

Step-by-step explanation:

Given equation of line is 2x-6y=7

To find point on graph whose x-coordinate twice the y-coordinate:

Let y be y-coordinate of point

Hence, x-coordinate of point will be 2y

The required point is P(2y,y) on equation of line 2x-6y=7

Now,

2x-6y=7

2(2y)-6y=7

-2y=7

y= $\frac{-7}{2}$

Thus,

The required point is P(-7, $\frac{-7}{2}$ )

Note: Figure show equation of line red line and point P as blue dot.

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