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Alchen [17]
3 years ago
9

Please answer will give brainliest

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

Otrada [13]3 years ago
7 0

Answer:

171

Step-by-step explanation:

I can give you the formula if u want

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At a canning facility, a technician is testing a machine that is supposed to deliver 250 milliliters of product. The technician
Serhud [2]

Answer:

The value of the test statistic is t = 1.97

Step-by-step explanation:

The null hypothesis is:

H_{0} = 250

The alternate hypotesis is:

H_{1} \neq 250

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the null hypothesis value, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 251.6, \mu = 250, \sigma = 5.4, n = 44

So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{251.6 - 250}{\frac{5.4}{\sqrt{44}}}

t = 1.97

The value of the test statistic is t = 1.97

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4 years ago
Please I need help!!! The Hiking Club plans to go camping in a State park where the probability of rain on
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Graph the following piecewise function and then find the range.
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4 years ago
George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at t
arsen [322]

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

6 0
4 years ago
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