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dsp73
3 years ago
5

A store sells blank T-shirts for $9.99 each. Buyers can customize shirts with holographic letters that cost 79 cents each. Alici

a wants to buy a t-shirt that says SAN DIEGO CHARGERS. How can she create a table and then use data from the table to enter an equation that will help her calculate the cost of the shirt?
Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

$420.69

Step-by-step explanation:

if you do some thinking, you'll easily find out the answer is $420.69

not only is it a funny number, it's also a NICE amount of cash i would really love to have. anyways, hope this helps!

P.S: i have all A's in school ;)

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Factor the trinomial x^2 - 7x + 10
Valentin [98]

Answer:

(x-5) (x-2)

Step-by-step explanation:

x^2 (-2x-5x) +10

basically you will write the equation down and then to double check multiply the x and then the -5 into (x-2). this can be repetitive if you get it wrong so try to do numbers that make sense.

7 0
3 years ago
Could someone check this again ​
ANTONII [103]

Answer:

yeah your right

Step-by-step explanation:

5 0
3 years ago
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in an examination of 140 students, 80 students passed mathematics,65 passed physics, 75 passed chemistry, 33 passed mathematics
Olegator [25]

Answer:

only I think 10 failed all courses

4 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
Help me asap i need it
s344n2d4d5 [400]

Answer:x = 56

Step-by-step explanation:

180-(60+64)=56

6 0
3 years ago
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