Answer: x = "-1 " ; <u>and</u>: "(1 ± √3) / 2" .
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Explanation:
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Given: 3x³ − 2x + 1 = 0 ; Find "x" ;
Factor: "3x³ − 2x + 1" ;
3x³ − 2x + 1 = (3x² <span>− 3x + 1)(x + 1) ;
Now, set the equation equal to "0" (zero);
</span> (3x² − 3x + 1)(x + 1) = 0 ;
x = 0 ; when:
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(x + 1) = 0 ; and/or: when:
(3x² − 3x + 1) = 0 ;
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Start with "x + 1 = 0" ;
Subtract "1" from each side of the equation ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ;
x + 1 − 1 = 0 − 1 ;
x = -1 ;
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Now, try:
3x² − 3x + 1 = 0 ;
Since: "3x² − 3x + 1 " cannot be factored; and since:
"3x² − 3x + 1 = 0" ; is written in the "quadratic equation format"; that is:
"ax² + bx + c = 0 ; a ≠ 0; We can use the "quadratic equation formula" to solve for "x" ;
in which "a = 3" ;
"b = -3" ;
"c = 1" ;
The quadratic equation formula is:
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x = [-b ± √(b²−4ac] / 2a ;
= ? (Let us plug in our known values for "a, b, & c"l
x = { [-(-3] ± [√[(-3²) − (4*3*1)] } / {2* 3} ;
x = [3 ± √(9 − 12)] / 6
x = [3 ± √(-3 )] / 6 ;
x = (1 ± √3) / 2 .
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So, the answers are: x = " -1 " ; and: "</span>(1 ± √3) / 2 " .
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The answer is C 528.
Hope this will help you
Answer:
Wow I feel dumb. I actually am stumped on this question... :(
Answer:
x= - 35 over 89
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2
7
x−23+5x=18(x−1)
2
7
x+−23+5x=(18)(x)+(18)(−1)(Distribute)
2
7
x+−23+5x=18x+−18
(
2
7
x+5x)+(−23)=18x−18(Combine Like Terms)
37
7
x+−23=18x−1837
7
x−23=18x−18
Step 2: Subtract 18x from both sides.
37
7
x−23−18x=18x−18−18x
−89
7
x−23=−18
Step 3: Add 23 to both sides.
−89
7
x−23+23=−18+23
−89
7
x=5
Step 4: Multiply both sides by 7/(-89).
(
7
−89
)*(
−89
7
x)=(
7
−89
)*(5)
x=
−35
89
Step-by-step explanation: