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Dmitry_Shevchenko [17]
3 years ago
6

What is the circumference? 18 yd

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:is 18 yd the radius

Step-by-step explanation:

if so its 113.1

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Write an equation to represent the following statement.
Hitman42 [59]

Answer:

51÷3 = k

17 =k

Step-by-step explanation:

is means equals

51÷3 = k

17 =k

7 0
4 years ago
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Rosario and Enrqiue are in the same mathematics
Paul [167]

Answer:Enrqiue's average was higher than Rosario's average by 3

Step-by-step explanation:

Rosario's average= sum of 78, 77, 64, 86, and 70/ no of scores= 375/5= 75

Enrique's average=sum of 90, 61, 79, 73, and 87/ no of scores = 390/5=78

78-75=3

3 0
4 years ago
Past records indicate that the probability of online retail orders
Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The mean of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that:

p = 0.08, n = 20

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

E(X) = np = 20*0.08 = 1.6

Standard deviation

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

P(X \leq 1) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

From itens b and c

P(X \leq 1) = 0.1887 + 0.3282 = 0.5169

P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831

48.31% probability that two or more online retail orders will turn out to be fraudulent.

4 0
4 years ago
SOME ONE PLEASE HELP!! step by step explanation
leva [86]

2.) 4y = 2y - 10 - 2

--> 4y = 2y - 8 --> 4y - 2y = -8 --> 2y = -8

So y = -4.

3.) 6x - 9x - 4 = -2x - 2

Combine like terms:

--> -3x - 4 = -2x - 2

Isolate x ---> -3x - (-2x) = -2 - (-4)

----> -x = 2

So x = -2

4.) -2(2x + 3) = -4(x + 1) - 2

--> -4x - 6 = -4x - 4 - 2

Combine like terms ---> -4x - 6 = -4x - 6

This equation has many possible solutions.

5.) 3(x + 2) = -5 - 2(x - 3)

--> 3x + 6 = -5 - 2x + 6

Combine like terms ---> 3x + 6 = -2x + 1

----> 3x + 2x = 1 - 6

-----> 5x = -5

So x = -1.

6.) 2(x - 3) = \frac{1}{2}(4x - 12)

Distribute ---> 2x - 6 = 2x - 6

This equation has many possible solutions.

4 0
3 years ago
Need done now !!!! WILL MARK BRAINLIEST!!!!!!!
maria [59]
P=2l+2w
P=2(120)+2(90)
P=240+180
P=420
420 feet of fencing is needed.
7 0
4 years ago
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