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adell [148]
3 years ago
9

You are using a hose to fill up your backyard swimming pool on a hot day. Water flows out of the hose at a rate of 6 gallons per

minute. In the equation below, m is the number of minutes the hose has been running, and g is the number of gallons of water in the pool.
The relationship between these two variables can be expressed by the following equation:
g=6m,
Identify the dependent and independent variables.
Mathematics
2 answers:
Katarina [22]3 years ago
7 0

Answer:

g=36

Step-by-step explanation:

so if g=6m you would do 6x6 as 6 gallons per minute and g is the amount in the pool so you times them to get 35 so g=36

telo118 [61]3 years ago
5 0

Answer:

The independent variable is the m, which is the number of minutes the hose has been running. The dependent variable is the g, which is the gallons per minute.

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What is perpendicular to -96/17
zzz [600]

Answer:

\frac{17}{96}

Step-by-step explanation:

Given  m = - \frac{96}{17}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{96}{17} } = \frac{17}{96}

6 0
3 years ago
The measures of the angles of a triangle are shown in the figure below. Solve for x.
ArbitrLikvidat [17]

Answer:

14

Step-by-step explanation:

5x-3+ x+9 + 90= 180

6x+ 96=180

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6x=84

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3 0
3 years ago
Factor completely 7x2-45x-28
MatroZZZ [7]

9514 1404 393

Answer:

  (x -7)(7x +4)

Step-by-step explanation:

The term -45x can be rewritten using factors of (7)(-28) that have a total of -45. Those factors would be ...

  (7)(-28) = (4)(-49)

7x^2 +4x -49x -28 = x(7x +4) -7(7x +4) = (x -7)(7x +4)

6 0
3 years ago
Tran checked the time on his watch after he finished his daily run select the time that Tran finished running mark all that appl
Viefleur [7K]

Answer:

(a) and (b) are correct

Step-by-step explanation:

Given

See attachment for complete question

Required

Select the correct options

A clock is divided into two equal parts.

(1) 1 - 6

(2) 7 - 12

<em>When the hour hand is on (1), then the time is "after"</em>

<em>When the hour hand is on (2), then the time is "before"</em>

<em />

From the attached clock, we have:

(1) The hour hand on 9

(2) The minute hand 1 unit above 9 i.e. 46 minutes

(1) implies that, the time is before 9 i.e. past 8

(2) implies that the minutes is (60 - 46) before 9 or 46 minutes after 8

In (1) and (2) above, we have two interpretations.

1: (60 - 46) minutes before 9

This gives:

14 minutes before 9

2: 46 minutes past 8

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3 0
3 years ago
A=3.14r^2 and d=12 A=?
zvonat [6]

\huge\boxed{113.04}

Diameter (d) is equal to twice the radius (r). So, find the radius by dividing \frac{12}{2}. The radius, or r, is 6.

Substitute in the value. A=3.14*6^2

Follow the order of operations and solve the exponent first. A=3.14*36

Multiply. A=\boxed{113.04}

4 0
4 years ago
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