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kirza4 [7]
3 years ago
10

Use the Trapezoidal Rule with n = 4 to approximate 0.3523 0.7048 0.2456 0.4913

Mathematics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

0.7048

Step-by-step explanation:

∫₂⁴ 1 / (x − 1)² dx

n = 4, so we divide the interval into 4 regions.  The width of the regions is:

(4 − 2) / 4 = 0.5

So the intervals are (2, 2.5), (2.5, 3), (3, 3.5) and (3.5, 4).

Evaluate f(x) at the ends of each interval.

f(2) = 1

f(2.5) = 4/9

f(3) = 1/4

f(3.5) = 4/25

f(4) = 1/9

Find the area of each trapezoid:

A₁ = ½ (2.5 − 2) (1 + 4/9) = 13/36

A₂ = ½ (3 − 2.5) (4/9 + 1/4) = 25/144

A₃ = ½ (3.5 − 3) (1/4 + 4/25) = 41/400

A₄ = ½ (4 − 3.5) (4/25 + 1/9) = 61/900

So the total approximate area is:

A = 0.705

Closest answer is 0.7048.

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tatiyna

Answer:

5^15

Step-by-step explanation:

Multiply the exponent that is inside the parentheses (3) by the exponent on the outside (9) to get 27 for the exponent, then subtract the exponent that is divided (12) to get an exponent of 15, which makes the answer 5^15.

3 0
3 years ago
An air-freshener starts with 21 grams and evaporates over time. In each of the following cases, enter a formula for the quantity
Ne4ueva [31]

Answer:

a.) Q= 21 - 7t

b.) Q = 21 - 1.26t

c.) Q = 21 - 2.1t

Step-by-step explanation:

a.) if it starts with 21grams, and it decreases with 7grams per day, then the remainder after t days becomes:

Q= 21 -7t.

For example, after one day, that is when t=1, the remainder becomes

Q= 21 - 7(1) = 14grams.

b.) if the decrease is 6% per day, we first calculate the 6% of 21, that is

21 * 6/100 = 1.26.

Hence, after t days, the remainder becomes:

Q= 21 - 1.26t.

For example, after 3 days, that is when t=3, the remainder becomes:

Q= 21 - 1.26(3) = 21 - 3.78

Q= 17.22grams.

c.) if the decrease is at 10% per day, and 10% of 21grams is 2.1grams, then the remainder becomes:

Q= 21 - 2.1t

3 0
3 years ago
Find AROC between -3 and -2
Alinara [238K]

Answer:(correct me if I'm wrong)

Answer: 1

Step-by-step explanation:

3 0
3 years ago
a box with a square base is taller than it is wide. in order to send the box through the US mail, the height of the box and the
NemiM [27]

The given box has the shape of a <u>cuboid</u>, since its <em>height</em> is greater than its <em>width</em>. Thus, the <em>maximum volume</em> for such box is 11200 in^{3}.

The <u>volume</u> of an object is a measure of it <em>containing</em> capacity. Since the given box has a taller <em>height</em> than its <em>width</em>, then it has the shape of a <em>cuboid</em>. The<u> volume</u> of a cuboid is given as:

volume = length x width x height

            = area x height

Given that the <u>sum</u> of the <em>perimeter</em> of its base and its <em>height</em> is not more than 108 inches, we can say; let the sides of the <em>square</em> base be represented by l and its height by h.

Then;

4l + h = 108

Therefore, maximum volume for the box can be attained when l = 20 inches and h = 28 inches.

So that;

4(20) + 28 = 80 + 28

                 = 108 inches

Thus;

maximum volume = area of the square base x height

                        = 400 x 28

maximum volume = 11200 in^{3}

The <u>maximum</u> <u>volume</u> for such a box would be 11200 in^{3}.

Visit: brainly.com/question/20463446

5 0
2 years ago
_____controls involve establishing specific goals given metrics and then measuring to what extent these goals are being achieved
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Answer:

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Step-by-step explanation:

8 0
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