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kirza4 [7]
3 years ago
10

Use the Trapezoidal Rule with n = 4 to approximate 0.3523 0.7048 0.2456 0.4913

Mathematics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

0.7048

Step-by-step explanation:

∫₂⁴ 1 / (x − 1)² dx

n = 4, so we divide the interval into 4 regions.  The width of the regions is:

(4 − 2) / 4 = 0.5

So the intervals are (2, 2.5), (2.5, 3), (3, 3.5) and (3.5, 4).

Evaluate f(x) at the ends of each interval.

f(2) = 1

f(2.5) = 4/9

f(3) = 1/4

f(3.5) = 4/25

f(4) = 1/9

Find the area of each trapezoid:

A₁ = ½ (2.5 − 2) (1 + 4/9) = 13/36

A₂ = ½ (3 − 2.5) (4/9 + 1/4) = 25/144

A₃ = ½ (3.5 − 3) (1/4 + 4/25) = 41/400

A₄ = ½ (4 − 3.5) (4/25 + 1/9) = 61/900

So the total approximate area is:

A = 0.705

Closest answer is 0.7048.

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HELP ME IM TERRIBLE AT THIS
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Answer:

a.   $14.50

b.  $43.5

Step-by-step explanation:

a. $7.00 + $7.50 = $14.50

b. y = 14.5x          x=3

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6. David gets 65 chocolates an hour for cleaning. He gets a 15% raise. He
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Answer:

Before raise: 65 chocolates/hour*60=3900 chocolates

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Step-by-step explanation:

7 0
2 years ago
-4r-8(r-6)=7(5r-1)+8
KATRIN_1 [288]

Answer:

r = 1

Step-by-step explanation:

In this question, we have to solve for the vallue of "r". We will use the distributive property shown below to ease our process.

Distributive Property:

a(b+c) = ab + ac

Now, lets solve this:

-4r-8(r-6)=7(5r-1)+8\\-4r-8r+48=35r-7+8\\-12r+48=35r+1\\48-1=35r+12r\\47=47r\\r=\frac{47}{47}\\r=1

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6 0
3 years ago
The mass of a species of mouse commonly found in houses is normally distributed with a mean of 20.2 grams with a standard deviat
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Answer:

12.1%

Step-by-step explanation:

Given that:

Mean (μ) = 20.2 grams and standard deviation (σ) = 0.18 grams.

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z=\frac{x-\mu}{\sigma}

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From the normal distribution table, P(x < 19.99) = P(z < -1.17) = 0.1210 = 12.1%

The probability that a randomly chosen mouse has a mass of less than 19.99 grams is 12.1%

6 0
3 years ago
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