I need some serious help with this asap!!! I will mark brainliest if right! Explain

$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned

Anettt [7]

Answer-

$2000 were invested at 5%

Solution-

Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%

We know that,

$i=\dfrac{P\cdot r\cdot t}{100}$

Putting the values,

$i_1=\dfrac{P_1\cdot r_1\cdot t}{100}$

$i_1=\dfrac{x\cdot 5\cdot 1}{100}=\dfrac{5x}{100}$

And

$i_2=\dfrac{P_2\cdot r_2\cdot t}{100}$

$i_2=\dfrac{(6000-x)\cdot 3\cdot 1}{100}=\dfrac{3(6000-x)}{100}$

According to the question,

$\Rightarrow \dfrac{5x}{100}+\dfrac{3(6000-x)}{100}=220$

$\Rightarrow \dfrac{5x+3(6000-x)}{100}=220$

$\Rightarrow 5x+3(6000-x)=22000$

$\Rightarrow 5x+18000-3x=22000$

$\Rightarrow 5x-3x=22000-18000$

$\Rightarrow 2x=4000$

$\Rightarrow x=2000$

Therefore, $2000 were invested at 5%

8 0

4 years ago

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Please help me I tried all day

pishuonlain [190]

1) Rent:
2200*0.3 = 660

2)Utilities:
2200/4 = 550

3)Transportation:
2200*0.1 = 220

4)Groceries:
2200*0.2 = 440

5)Entertainment:
2200*0.1 = 220

6)Other:
2200/20 = 110

Thus the thing that costs 550 is the utilities.
Hope this helps! :)

7 0

3 years ago

What Is The Recursive Rule For The Sequence? 1.2, 0.4, -0.4, – 1.2, -2,

nevsk [136]

<h3>Answer:</h3>

$\boxed{\bold{a_n = a_{n-1} -0.8}}$

<h3>Explanation:</h3>

Sequence: 1.2, 0.4, -0.4, – 1.2, -2,...

See that with every next term, the integers are decreasing by 0.8

So, common difference (d) = -0.8

recursive formula : $\sf a_n = a_{n-1} +d$

$\bold a_1 = 1.2,$ $\sf a_n = a_{n-1} + (-0.8)$

8 0

2 years ago

Find set A={1, 2, 6, 10} B={3, 6, 9, 10, 11} C = {1, 2, 4, 7, 11}

PilotLPTM [1.2K]

If U = {1, 2, 3, …, 12} is the universal set, and

A = {1, 2, 6, 10}

B = {3, 6, 9, 10, 11}

C = {1, 2, 4, 7, 11}

then

(1) A U B is the set containing all elements from A and B,

A U B = {1, 2, 3, 6, 9, 10, 11}

(2) A ∩ B is the set of elements that are contained in both A and B,

A ∩ B = {6, 10}

(3) Unfortunately, A ∩ B U C is somewhat ambiguous. It could mean (A ∩ B) U C or A ∩ (B U C ). Then either

(A ∩ B) U C = {6, 10} U {1, 2, 4, 7, 11} = {1, 2, 4, 6, 7, 10, 11}

or

A ∩ (B U C ) = {1, 2, 6, 10} ∩ {1, 2, 3, 4, 6, 7, 9, 10, 11} = {1, 2, 6, 10}

The first interpretation is probably the intended one, since that essentially reads the set operations from left to right.

(4) A' U B is the union of A' and B, where A' is the complement of A, or all elements in U that are not in A. We have

A' = U - A = {3, 4, 5, 7, 8, 9, 11, 12}

and so

A' U B = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(5) We have

A U C = {1, 2, 4, 6, 7, 10, 11}

so that

(A U C )' = U - (A U C ) = {3, 5, 8, 9, 12}

(6) We have

B' = U - B = {1, 2, 4, 5, 7, 8, 12}

and so

A ∩ B' = {1, 2}

(7) Using the complements found in (4) and (6), we have

A' U B' = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

Alternatively, we can use the fact that

A' U B' = (A ∩ B)'

and since we know from (2) that A ∩ B = {6, 10}, we end up with the same result,

(A ∩ B)' = U - (A ∩ B) = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

(8) We have

A U B U C = {1, 2, 3, 4, 6, 7, 9, 10, 11}

so that

(A U B U C )' = {5, 8, 12}

6 0

3 years ago

In a certain chemical, the ratio of zinc to copper is 3 to 16 . A jar of the chemical contains 416 grams of copper. How many gr

Anna71 [15]

Answer:

the number of grams of zinc contain is 78

Step-by-step explanation:

The computation of the number of grams of zinc contain is shown below:

Given that the ratio of zinc to copper is 3:16

And, the jar of the chemical has 416 grams copper

So, the number of zinc grams would be

here we assume the zinc grams be x

Now the equation would be

3 ÷ 16 = x ÷ 416

Now applied the cross multiplication

16x = 416 × 3

x = (416 × 3) ÷ 16

= 78

Therefore the number of grams of zinc contain is 78

7 0

3 years ago

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