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ANTONII [103]
2 years ago
9

Crich Corporation uses direct labor-hours in its predetermined overhead rate. At the beginning of the year, the estimated direct

labor-hours were 21,800 hours and the total estimated manufacturing overhead was $497,040. At the end of the year, actual direct labor-hours for the year were 21,500 hours and the actual manufacturing overhead for the year was $492,040. Overhead at the end of the year was: (Round your intermediate calculations to 2 decimal places.)
Business
1 answer:
Brrunno [24]2 years ago
6 0

Answer:

Underapplied overhead= $1,640

Explanation:

<u>First, we need to calculate the predetermined overhead rate:</u>

Predetermined manufacturing overhead rate= total estimated overhead costs for the period/ total amount of allocation base

Predetermined manufacturing overhead rate= 497,040 / 21,800

Predetermined manufacturing overhead rate= $22.8 per direct labor hour

<u>Now, we can allocate overhead:</u>

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

Allocated MOH= 22.8*21,500

Allocated MOH= $490,200

<u>Finally, the over/under allocation:</u>

Under/over applied overhead= real overhead - allocated overhead

Under/over applied overhead= 492,040 - 490,200

Underapplied overhead= $1,640

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4 0
3 years ago
Let S represent the amount of steel produced (in tons). Steel production is related to the amount of labor used (L) and the amou
Phantasy [73]

Solution

S = 15 x L^{0.2} x C^{0.8}

Total cost, T = wL + rC = 50L + 100C

Total revenue, R = Output price (P) x Quantity = P x 15 x L^{0.2}x C^{0.8}

(a)

Optimization problem will be:

Max R = P x 15 x L^{0.2} x C^{0.8}

Subject to T = 50L + 100C

(b) When S = 50,000

Cost is minimized when (MPL / MPC) = w / r

MPL = \partialR / \partialL = P x 15 x 0.2 x (C / L)^{0.8} = P x 3 x (C / L)^{0.8}

MPC = \partialR / \partialC = P x 15 x 0.8 x (L / C)^{0.2} = P x 12 x (L / C)^{0.2}

MPL / MPC = (3/12) x (C / L) = 50/100

C / 4L = 1/2

4L = 2C

2L = C

Substituting in production function,

15 x L^{0.2} x C^{0.8} = S

15 xL^{0.2} x (2L)^{0.8} = 50,000

15 x 2^{0.8} x L^{0.2} x L^{0.8} = 50,000

L = 50,000 / (15 x 20.8)

L = 1,914.50

C = 2L = 3,829.00

Total cost ($) = 50 x 1,914.50 + 100 x 3,829.00 = 95,725.00 + 382,900 = 478,625.00

Note: This optimization problem can be solved without using Solver too, as shown here.

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