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Elena-2011 [213]
4 years ago
12

Last week, Clay wrote 4 checks for $20 each from his checking account and

Mathematics
1 answer:
Sidana [21]4 years ago
5 0

Answer:

Step-by-step explanation:

clay will have

-80+96=16 dollars

the change in balance is +16

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Metric unit for the mass of a television
Ilia_Sergeevich [38]
I would say kilograms, becauee kilograms would be the best metric unit for the mass of a television.
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What is 709÷31= and 50÷409
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28.87 and .122
Hope this helps
6 0
4 years ago
Read 2 more answers
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Anthony has a combination of 104 nickels and quarters totaling $22. Which system of linear equations can be used to find the num
Nana76 [90]

Answer:

x + y = 104

0.05x + 0.25y = 22

x = 20 niquels and y = 84 quarters

Step-by-step explanation:

Each niquel is $0.05, and each quarter is $0.25

So if we have x niquels and y quarters, we can set this system of equations:

x + y = 104 (eq1)

0.05x + 0.25y = 22 (eq2)

If we multiply the second equation by 4, and then subtract it from the first equation, we have:

(eq2)*4:    0.2x + y = 88

(eq1) - 4*(eq2):    0.8x = 16

x = 20

Now finding y with the first equation:

20 + y = 104

y = 84

4 0
4 years ago
Read 2 more answers
The cheerleaders are making a banner that is 8 feet wide. The length of the banner is 1 1/3 times width of the banner. How long
eduard

Answer:

The banner is 10 2/3 ft long

Step-by-step explanation:

1 1/3 = 4/3 times the width of the banner:

4/3 * 8 feet wide = 4/3 * 8 = 32/3 = 10 2/3 feet long

The banner is 10 2/3 feet long. :)

3 0
4 years ago
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