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Stolb23 [73]
3 years ago
13

HELP!! Image inculded

Mathematics
1 answer:
fomenos3 years ago
6 0

Answer:

<h2>B.</h2>

\frac{ - 3}{ {x}^{2} - 5x + 6 }

hope it helps

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Plisss help write the linear equation that vives the rule for this table ​
sineoko [7]

well, we know is a line,  and to get the equation of any straight line all we need is two points, hmmm let's use from the table hmm say (2 , -50) and hmmm (4 , -88)

(\stackrel{x_1}{2}~,~\stackrel{y_1}{-50})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-88}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-88}-\stackrel{y1}{(-50)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{2}}}\implies \cfrac{-88+50}{2}\implies \cfrac{-38}{2}\implies -19

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-50)}=\stackrel{m}{-19}(x-\stackrel{x_1}{2}) \\\\\\ y+50=-19x+38\implies y=-19x-12

5 0
2 years ago
??? help plssss ???? ​
yulyashka [42]

Answer:

18

Step-by-step explanation:

12(3/2)=36/2=18

7 0
3 years ago
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A student used a 30% off coupon to buy a jacket. There was no tax. The student paid $67.34. What was the original price of the j
PSYCHO15rus [73]

Step-by-step explanation:

the solution is in the picture

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3 years ago
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You are tutoring a classmate in subtracting fractions. How might you summarize the rules for subtracting fractions with like den
maw [93]
To subtract fractions, let's put a generic example.
 Be the fractions
 (a / b) - (c / d)
 With a, b, c and d other than zero.
 The subtraction of fractions is given by:
 (a / b) - (c / d) = ((a * d) - (c * b)) / (b * d).
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 answer
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7 0
3 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
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