Help !! 10 points!! :)
1 answer:
You might be interested in
Answer: 90.82%
Step-by-step explanation:
Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .
Mean :
Standard deviation:
Let X be the random variable that represents the amount of soda in bottles.
Formula for z-score :
Z-score for 16 oz:
Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_
Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .