Y=2(-1)^2-6(-1)+3
y=2+6+3
y=8+3
y=11
Given:
p = 20% = 0.2, sample proportion
n = 5000, sample size.
Confidence level = 95%
The confidence interval is
(p - 1.96k, p + 1.96k)
where

Therefore the 95% confidence interval is
(0.1943, 0.2057) = (19.4%, 20.6%)
Answer: The 95% confidence interval is (19.4%, 20.6%)
The percentage of the radioactive isotope left is 25.0000%.
<h3>What is the half life?</h3>
The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.
Now;
We are told that;
Half life (t1/2) = 55 days
Time taken (t) = 115 days
Ratio of isotope remaining = N/No
Thus;
N/No = (1/2)^t/t1/2
N/No = (1/2)^115/55
N/No = (1/2)^2
N/No =1/4
Hence, the percentage = 1/4 * 100/1 = 25.0000%
Learn more about half life of an isotope:brainly.com/question/16387602
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This question calls for a fraction. In a fraction, the numerator (top number) is the number of parts, while the denominator (bottom number) is the total number of parts. One part is one glass of milk, and there are 12 parts total. So, we get the answer 1/12.
Answer: 1/12
The regression equation of Y on X is given by the following formula:

Where byx is given by the formula:

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.
The table of values is:
The values we need to know are on the following table:
By replacing the known values in the formula we obtain:

Now, the average of X and Y is the sum divided by N, then:

Replace these values in the formula and find the regression equation as follows:

The answer is a) y=4.6x+28.26