Question

Find the height of ABD

Answer 1

Answer:

$Height=\boxed{10\sqrt{2}}$

$Area =\boxed{165\sqrt{2}}$

Step-by-step explanation:

By geometric mean theorem:

$AC=\sqrt{25\times 8}$

$AC=\sqrt{5^2 \times 2^2 \times 2}$

$AC=5\times 2\sqrt{2}$

$AC=10\sqrt{2}$

So,

$Height=\boxed{10\sqrt{2}}$

$Area = \frac{1}{2} \times base\times height$

$\therefore Area = \frac{1}{2} \times (25+8)\times 10\sqrt{2}$

$\therefore Area =33\times 5\sqrt{2}$

$Area =\boxed{165\sqrt{2}}$