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1 year ago

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The small submarine is at –1,320 feet in relation to sea level. The submarine needs to be at 180 feet below sea level in 60 minu

tes.
What does the average rate of ascent need to be?

1 answer:

larisa [96]1 year ago

3 0

Answer:

The first submarine needs to travel at a rate of [-180 – (-1,320)] ÷ 60 = 19 feet per minute. The second submarine needs to travel at a rate of [-180 – (-1,440)] ÷ 60 = 21 feet per minute.

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago

algol [13]

Answer:

1:350 i think

Step-by-step explanation:

i could be wrong

7 0

1 year ago

Read 2 more answers

Q # 9 please find the area

Rudik [331]

To solve this problem you must apply the formula for calculate the surface area of a circle, which is shown below:
SA=πir^2
where r is the radius of the circle
r=18 inches
By substituying values, you have that the surface area is:
SA=π(18 in)^2
SA=324π in^2
The answer is 324π in^2

6 0

2 years ago

Read 2 more answers

Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is

$f(x)=\begin{cases}0&0\leq x$ .

To show that the convergence is not uniform consider $0$ . For any $n>1$ choose $x\in (0,1)$ such that $\varepsilon^{1/n}$ . Then

$\varepsilon$

This implies that the convergence is not uniform.

8 0

2 years ago

Which situation could be solved using the equation -4+4=0

navik [9.2K]

we are supposed to explain

Which situation could be solved using the equation $-4+4=0$

As we can see in the given equation , one number is -4 and the other number is 4

When we add two number of same value but opposite in sign we get zero.

This equivalent to the real life situation of paying a post paid bills.

Suppose you are using a post paid service , and the bills gets generated at the end of the month.

Suppose the bills amount is $x.

Once you pay that bills , then total outstanding again becomes $0.

Because $-x+x=0$

5 0

2 years ago