Question

The small submarine is at –1,320 feet in relation to sea level. The submarine needs to be at 180 feet below sea level in 60 minutes.
What does the average rate of ascent need to be?

Answer 1

Answer:

The first submarine needs to travel at a rate of [-180 – (-1,320)] ÷ 60 = 19 feet per minute. The second submarine needs to travel at a rate of [-180 – (-1,440)] ÷ 60 = 21 feet per minute.