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PolarNik [594]
3 years ago
11

Write in expanded form. Use parentheses to indicate multiplication.

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

Yung utak mo sabog hahahaha

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Solve the equation for x 23=5-2y
GaryK [48]

23=5-2y

Get y alone,

23-5= 18

18= -2y

Divide to find y

18/-2=-9

Y= -9


Or since you asked for x, X=no solutions.


Hope it helps ❤️

3 0
3 years ago
What is the perimeter of a triangle 5x5x5?
Simora [160]

Answer:

15

Step-by-step explanation:

3 0
3 years ago
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What is m Enter your answer in the box.
MariettaO [177]

Answer:

Step-by-step explanation:

I don't say u must have to mark my ans as brainliest but if u think it has really helped u plz don't forget to thank me...

8 0
3 years ago
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A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\

\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
4 years ago
Have a great day everyone
kakasveta [241]

Answer:

U too fellow human

Step-by-step explanation:

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3 years ago
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