Given that a || b, m∠2 = 63° and m∠9 = 105°.
Now, all the angles are as follows:
m∠5=
m∠2 = 63° [vertically opposite angle]
m∠7=
m∠9=105° [vertically opposite angle]
m∠8=
180°-m∠9=180°-105°=75° [Supplementry angles, m∠8+m∠9=180°]
m∠10=
m∠8=
180° [vertically opposite angle]
m∠6=
m∠8=75° [ Alternate angles]
m∠3=
m∠6=75° [vertically opposite angle]
m∠1=
180°-(m∠2+m∠3)=180°-(63°+75°)=42° [as m∠1+m∠2+m∠3=180°]
m∠4=
m∠1=42° [vertically opposite angle]
m∠11=m∠4=42° [ Alternate angles]
m∠13=
m∠11=42° [vertically opposite angle]
m∠12=
180°-m∠11=180°-42°=138° [as m∠8+m∠9=180°]
m∠14 =
m∠12=138° [vertically opposite angle]
Answer:
There are 336 ways can the teams finish first, second, and third
Step-by-step explanation:
Total no. of teams = 8
First prize is given to one of the 8 teams
So, no. of teams left for second prize = 8-1 =7
Second prize is given to one of the remaining 7 teams
So, no. of teams left for third prize = 7-1=6
So,the teams finish first, second, and third in no. of ways =
The teams finish first, second, and third in no. of ways = 336
Hence there are 336 ways can the teams finish first, second, and third
Neither. They can’t be parallel because both lines have different slopes. They aren’t perpendicular either because their slopes don’t multiply to equal -1.
Answer:
I'm not 100% sure but I think it's C.
it might also be B. it's one of those 2 for sure but I'm like %80 sure it’s C.
Step-by-step explanation:
please let me know if im right or wrong....
