(2x)^4 = 16x^4 is the continued product
Assuming that the triangle is a right triangle, we can reverse engineer the Pythagorean theorem (a^2+b^2=c^2).
60^2 + x^2 = 61^2
3600 + x^2 = 3721
x^2 = 3600 - 3721
x^2 = 121
x = sqrt121
x = 11
Is that the full question? I can't solve it if s is a variable
