In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.
1 answer:
Answer:
in triangle BCD
relationship between base and hypotenuse is given by cos angle
cos 71=b/h
cos71=BD/BC
cos71=67/x
x=67/cos71=205.8ft.
the length of BC to the nearest tenth of a foot is 206ft.
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