If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
6 × 9 ÷ 18 + 100 - 11 + 4
Use the order of operations to simplify:
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
6 × 9 ÷ 18 + 100 - 11 + 4
There are no parentheses or exponents, so multiplication comes first. Multiply 6 and 9.
54 ÷ 18 + 100 - 11 + 4
Next is division. Divide 54 by 18.
3 + 100 - 11 + 4
Finally, add and subtract from left to right.
103 - 11 + 4
92 + 4
96
<h3>
Answer:</h3>
96
A. X Z Y
B. P N M
C. F E H G D
Answer:
68
Step-by-step explanation:
Multiply the numbers to get the area
R = speed in still water
r + c = speed with current
r - c = speed against current
3.5(r + c) = 70
r + c = 20
c = 20 - r
4(r + c) = distance from pier to pier
5(r - c) = distance from pier to pier
4(r + c) = 5(r - c)
4(r + 20 - r) = 5(r - 20 + r)
80 = 10r - 100
180 = 10r
18 = r
The speed in still water is 18 km/hour