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katrin2010 [14]

3 years ago

14

Market so seven oranges for $2.45 how much would 8 oranges cost

1 answer:

Irina18 [472]3 years ago

8 0

Answer:

8 oranges will cost $2.80.

Step-by-step explanation:

2.45/7=0.35

2.45+0.35=2.80

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Evaluate-a-function f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B7%7D" id="TexFormula1" title="\frac{x}{7}" alt="\f

OLga [1]

Step-by-step explanation:

Hey there!

f(x) = 7/x

<em>~ Simply keep the "7" in the place where "x" is there.</em>

$f(7) = \frac{7}{7}$

Therefore, X= 1.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0

3 years ago

Read 2 more answers

What is the length of AB?

kozerog [31]

Answer: 6 units

Step-by-step explanation:

I know that in a triangle, there's two angles that have equal measures, then the sides opposite to them are equal in length. Thus, the length of side AB is 6 units.

8 0

3 years ago

Read 2 more answers

Find a power series for the function, centered at c, and determine the interval of convergence. f(x) = 9 3x + 2 , c = 6

san4es73 [151]

Answer:

$\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ........$

The interval of convergence is: $(-\frac{2}{3},\frac{16}{3})$

Step-by-step explanation:

Given

$f(x)= \frac{9}{3x+ 2}$

$c = 6$

The geometric series centered at c is of the form:

$\frac{a}{1 - (r - c)} = \sum\limits^{\infty}_{n=0}a(r - c)^n, |r - c| < 1.$

Where:

$a \to$ first term

$r - c \to$ common ratio

We have to write

$f(x)= \frac{9}{3x+ 2}$

In the following form:

$\frac{a}{1 - r}$

So, we have:

$f(x)= \frac{9}{3x+ 2}$

Rewrite as:

$f(x) = \frac{9}{3x - 18 + 18 +2}$

$f(x) = \frac{9}{3x - 18 + 20}$

Factorize

$f(x) = \frac{1}{\frac{1}{9}(3x + 2)}$

Open bracket

$f(x) = \frac{1}{\frac{1}{3}x + \frac{2}{9}}$

Rewrite as:

$f(x) = \frac{1}{1- 1 + \frac{1}{3}x + \frac{2}{9}}$

Collect like terms

$f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2}{9}- 1}$

Take LCM

$f(x) = \frac{1}{1 + \frac{1}{3}x + \frac{2-9}{9}}$

$f(x) = \frac{1}{1 + \frac{1}{3}x - \frac{7}{9}}$

So, we have:

$f(x) = \frac{1}{1 -(- \frac{1}{3}x + \frac{7}{9})}$

By comparison with: $\frac{a}{1 - r}$

$a = 1$

$r = -\frac{1}{3}x + \frac{7}{9}$

$r = -\frac{1}{3}(x - \frac{7}{3})$

At c = 6, we have:

$r = -\frac{1}{3}(x - \frac{7}{3}+6-6)$

Take LCM

$r = -\frac{1}{3}(x + \frac{-7+18}{3}+6-6)$

r = -\frac{1}{3}(x + \frac{11}{3}+6-6)

So, the power series becomes:

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}ar^n$

Substitute 1 for a

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}1*r^n$

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}r^n$

Substitute the expression for r

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}(-\frac{1}{3}(x - \frac{7}{3}))^n$

Expand

$\frac{9}{3x + 2} = \sum\limits^{\infty}_{n=0}[(-\frac{1}{3})^n* (x - \frac{7}{3})^n]$

Further expand:

$\frac{9}{3x + 2} = 1 - \frac{1}{3}(x - \frac{7}{3}) + \frac{1}{9}(x - \frac{7}{3})^2 - \frac{1}{27}(x - \frac{7}{3})^3 ................$

The power series converges when:

$\frac{1}{3}|x - \frac{7}{3}| < 1$

Multiply both sides by 3

$|x - \frac{7}{3}|$

Expand the absolute inequality

$-3 < x - \frac{7}{3}$

Solve for x

$\frac{7}{3} -3 < x$

Take LCM

$\frac{7-9}{3} < x$

$-\frac{2}{3} < x$

The interval of convergence is: $(-\frac{2}{3},\frac{16}{3})$

6 0

3 years ago

Write the equation of a circle that has a center of (-8, 0)<br> and a diameter of 8.

Sveta_85 [38]

Answer:

(x+8)^2+y^2=16

Step-by-step explanation:

The equation for a circle in center-radius form is

(x-h)^2+(y-k)^2=r^2

where (h,k) is the center and r is the radius.

We are given the diameter is 8 so the radius is 8/2=4.

We are also given (h,k) is (-8,0).

The equation for the circle is

(x--8)^2+(y-0)^2=4^2

(x+8)^2+y^2=16

8 0

3 years ago

HELP...The volume of a rectangular prism is 36x^6y^8. The length of the prism is 4x^3y^5, and the width of the prism is 3xy^2. W

Margaret [11]

Answer:

$H = 3x^2y$

Step-by-step explanation:

Given

$V = 36x&^6y^8$

$L = 4x^3y^5$

$W = 3xy^2$

Required

Find the height of the prism

Volume (V) is calculated as:

$V =LWH$

Substitute values for V, L and W

$36x^6y^8 =4x^3y^5 * 3xy^2 * H$

Make H the subject

$H = \frac{36x^6y^8}{4x^3y^5 * 3xy^2}$

$H = \frac{36x^6y^8}{4*3x^3*x*y^5y^2}$

$H = \frac{36x^6y^8}{12x^4*y^7}$

Divide:

$H = 3x^{6-4}y^{8-7}$

$H = 3x^2y$

The height of the prism is: $3x^2y$

4 0

3 years ago