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4 years ago

14

Solve the equations and find the solutions -15+50=6-3x

1 answer:

Wewaii [24]4 years ago

5 0

-15+50=6-3x

simplify
35 = 6 - 3x

rewrite
6 - 3x = 35

Subtract 6 to both sides
6 - 3x - 6 = 35 -6

Simplify
-3x = 29

Divide both sides by -3
-3x/3 = 29/-3

Simplify
x = -29/3
x = -9 2/3

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3 years ago

An Xത chart with three-sigma limits has parameters as follows: UCL = 104; Center Line = 100; LCL = 96; n = 5 Suppose the process

ruslelena [56]

Answer:

The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.

Step-by-step explanation:

We consider "lack of control by at least the third point plotted" if at least one of the three first points is over the UCL or under the LCL.

The probability of one point of being over UCL=104 is:

$z=(X-\mu)/\sigma=(104-98)/8=6/8=0.75\\\\P(X>104)=P(z>0.75)=0.227$

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Then, the probability of exhibit lack of control is:

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The probability of having at least one point out of control in the first three points is:

$P(x\geq1)=1-P(0)\\\\P(x\geq1)=1- 0.052=0.948\\\\\\P(x=0) = \binom{11}{0} p^{0}q^{3}= 1*1*0.0515=0.0515\\\\$

The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.

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3 years ago