3 years ago

I WILL GIVE BRAINLIEST❤️

Mathematics

2 answers:

Irina-Kira [14]3 years ago

5 0

sorry

además no ablo mucho inglés

kati45 [8]3 years ago

3 0

Answer:

divide.

Step-by-step explanation:

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Y-(5-(y-x)) x = 4 y = 6 I need the steps please, this is a little bit confusing..

KATRIN_1 [288]

Answer:

Step-by-step explanation:

substitute x = 4 , y = 6 into the expression

y - (5 - (x - y))

= 6 - (5 - (6 - 4))

= 6 - (5 - 2))

= 6 - 3

= 3

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2 years ago

vitfil [10]

I need the paragraph bro bro

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4 years ago

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HELP!! And please explain thanks

ohaa [14]

pic the second one to your left and youll find ur answer

7 0

4 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

7 0

4 years ago

Plz and thank you I need help

suter [353]

Answer:

ummm there is nothing

Step-by-step explanation:

5 0

3 years ago

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