P = 2(L + W)
L = W + 5
A = 4P + 2
P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10
A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42
A = L * W
A = W(W + 5)
A = W^2 + 5W
W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0
W - 14 = 0
W = 14 <==
L = W + 5
L = 14 + 5
L = 19 <==
P = 2(19 + 14)
P = 2(33)
P = 66
A = L * W
A = 19 * 14
A = 266
answer : length = 19, width = 14....perimeter = 66....area = 266
Answer: No, the money won't be enough to buy the car
Step-by-step explanation:
you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.
The principal amount, p = 300
He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So
n = 4
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for a total of 24 months. This is equivalent to 2 years. So
n = 2
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount that would be compounded at the end of n years.
A = 300(1 + (0.04/4)/4)^4×2
A = 300(1 + 0.01)^8
A = 300(1.01)^8
A = $324.857
The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car
15x - 5y = 1 it's B in standard form
Find the critical value or test statistic.

Find P(z > 2.25) using a normal distribution table
P(z > 2.25) = 0.0122
Answer:
The slope of this line will be y=-3/4x+3
Step-by-step explanation:
Hope this Helped