108<9•12
^. ^
3•3 2•6
^. ^
1•2 3•2
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
The second option would be parallel
Michael will have 4 cards left because 265/9=29.4444444... then i do 29 (from the 29.4444) times 9 which gives me 261 and i did 265-261.
9514 1404 393
Answer:
(a) = 7 +3·5
Step-by-step explanation:
The given expression evaluates to ...
6 +2^4 = 6 +16 = 22
The offered choices evaluate to ...
7 +3·5 = 7 +15 = 22
4·10^3 +96 = 4·1000 +96 = 4096
7^2 = 49
3·10 +2 = 30 +2 = 32
The only choice that will form a proper equation is the expression that evaluates to 22:
6 +2^4 = 7 +3·5
