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3 years ago

3x+8y=15 , 2x−8y=10

Mathematics

2 answers:

faltersainse [42]3 years ago

3 0

I think is should be (5,0)

Elden [556K]3 years ago

3 0

Hello :)

The solution to these equations is (5,0)

Hope this helps and have a great day!

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NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.

PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

$y = 3x$

We want everything below this line (line included), so the first inequality is

$y \leq 3x$

The line between the origin and B is

$y = \dfrac{1}{3}x$

We want everything above this line (line included), so the second inequality is

$y \geq \dfrac{1}{3}x$

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

$A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}$

Which means

$A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}$

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

$B:\ 1$

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0

2 years ago

(02.03) A bicyclist rides 16 miles in 144 minutes. If she continues at this speed, how long will it take her to travel 36 miles?

lubasha [3.4K]

186 miles in that time

7 0

3 years ago

Read 2 more answers

Can you please help me solve and if you show work I would really appreciate it

Anettt [7]

You got the equations correct, great job on that!

Let "s" be the variable that represents how many shirts were bought. Let "p" represent the total price/cost.

Equation for the store at Town Center mall:

p = 80 + 3.5s (80 is base cost, and cost increases 3.5 per shirt)

Equation for the store in Arlington:

p = 120 + 2.5s (120 is base cost, and cost increases 2.5 per shirt)

We want to find a point where the systems are equal; thus, we are solving for a system of linear equations, and we already have the equations we need.

p = 80 + 3.5s

p = 120 + 2.5s

We know that variable "p" is equal for both equations; thus, we can combine both equations into:

80 + 3.5s = 120 + 2.5s

Subtract both sides by 2.5s

80 + 3.5s - 2.5s = 120 + 2.5s - 2.5s

80 + s = 120

Subtract both sides by 80

s = 40

Thus, both equations are equal when 40 shirts are bought.

To find the cost, use any of the two equations (or both) to find the total cost, which should be equal.

p = 80 + 3.5(40) = 220

p = 120 + 2.5(40) = 220

Thus, the total price/cost at both stores is $220.

Let me know if you need any clarifications, thanks!

8 0

3 years ago

What statement is valid….

Nataly_w [17]

Discuss the relevance of fairy tales in society today and the aspects that it teaches us about our world. Why do we enjoy fairy tales and repeat these stories over time? How do fairy tales open our eyes to other cultures? What does it mean to live happily ever after? Discuss why tricksters often highlight flaws in the gods. If tricksters threaten order, authority, and hierarchy, then why do you think they appear in various stories? What are the similarities and differences in intelligence between the gods and tricksters? Discuss the ways in which tricksters mediate between the gods and men. Why do you think tricksters take the side of humans? What do the trickster stories say about cunning? Can intelligence be both evil and good?

3 0

2 years ago

Help here too please

lyudmila [28]

What’s the question

7 0

3 years ago