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o-na [289]
3 years ago
9

Which function is symmetric with respect to the origin?

Mathematics
1 answer:
icang [17]3 years ago
8 0
We need options to answer
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The area of a piece of cloth is 3/4 inches. The width is 1/2 inch. What is the length
nikitadnepr [17]

Answer:

3/2

Step-by-step explanation:

3/4÷1/2=3/2

6 0
4 years ago
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The quotient of forty-three and a number m
Tcecarenko [31]

Answer:

<u>43/m</u>

Step-by-step explanation:

  • Quotient refers to the resulting answer when a number is divided by a   divisor
  • In this case, our number is 43 and divisor is m
  • Therefore, the quotient is :
  • <u>43/m</u>
7 0
3 years ago
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How would you write x + y = 2, x + 2y = 3 as a word problem?
sveticcg [70]

Answer: x+y=

Step-by-step explanation:

you would just write it out step by step explaining wht u need to do to solve the question

7 0
2 years ago
If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball c
RoseWind [281]

Answer:

<h2>124.1m</h2>

Step-by-step explanation:

29.4 per sec > Building 80m

Height = S = 4.9t^2 + 29.4t + 80

Solve for t:

t = 1.24 (approximately)

If t needed coordinates / solve using the quadratic formula:

t = (1.24 , -7.24)

<h3>The ball's maximum height is 124.1 meters.</h3>
7 0
3 years ago
Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.
Georgia [21]

Answer:

D

Step-by-step explanation:

First, let's find <em>x</em>.

We know that one of the angles is 30. The side opposite to than angle is 11, and <em>x</em> is the adjacent side to it. Therefore, we can use the trig function tangent.

Recall that:

\tan(x)=opp/adj\\

Plug in 30 for the angle, 11 for the opposite, and <em>x</em> for the adjacent. Solve for <em>x</em> by cross-multiplying:

\tan(30)=11/x\\x\tan(30)=11\\x=11/\tan(30)

From the unit circle, recall that tan(30) is equal to one over the square root of 3. Thus:

x=11/(1/\sqrt3)\\x=11\cdot\sqrt3\\x=11\sqrt3

Now, we can use the Pythagorean Theorem to find <em>y</em>. <em>y</em> is the hypotenuse. Thus:

c^2=a^2+b^2\\c^2=(11\sqrt3)^2+11^2\\c^2=121(3)+121\\c^2=4(121)\\c^2\sqrt{4(121}=2(11)=22

6 0
3 years ago
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