The answer is 191/30
5 x 10 for easy points
2 answers:
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Answer:
Step-by-step explanation:
We know that normal distribution as special characteristics such as symmetry, unimodal, no skewness, mean =median=mode, etc
A standardized variable for normal variable X is
will be normal with mean =0 and sigma =1
The probability will be divided equally on either side of the mean =0 i.e. y axis
Hence the answers would be
A standardized variable always has a mean of __0_____ and a standard deviation of ___1____. b. The z-score corresponding to an observed value of a variable tells you ____the std normal score.___. c. A positive z-score indicates that the observation is __to the right ____ the mean, whereas a negative z-score indicates that the observation is __to the left_____ the mean
Answer:
The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is 0.6065.
Step-by-step explanation:
The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.
The random variable <em>T</em> is exponentially distributed.
The probability density function of a an exponential random variable is:
The average time a customer spends in a bank is <em>β</em> = 10 minutes.
Then the parameter of the distribution is:
An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.
That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)
So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is:
P (X > 15 | X > 10) = P (X > 5)
Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes is 0.6065.