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Katena32 [7]
3 years ago
8

Please help me with this ​

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

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In 1981, the Australian humpback whale population was 350 and has increased at a rate of 14% each year since then.)
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Answer:

In 1981, the Australian humpback whale population was 350

Po = Initial population = 350

rate of increase = 14% annually

P(t) = Po*(1.14)^t

P(t) = 350*(1.14)^t

Where

t = number of years that have passed since 1981

Year 2000

2000 - 1981 = 19 years

P(19) = 350*(1.14)^19

P(19) = 350*12.055

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Year 2018

2018 - 1981 = 37 years

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P(37) ≈ 44622

There would be about  44622  humpback whales in the year 2018

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Step-by-step explanation:

19 is the answer I think so

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