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Komok [63]
3 years ago
13

How many solutions does the following equation have? -5(z+1)=-2z+10−5(z+1)=−2z+10

Mathematics
1 answer:
Levart [38]3 years ago
7 0

Step-by-step explanation:

the answer is 13 when we evaluate it

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Mrs. Hudson plans to give a 10 question multiple choice exam in which each question has 4 options. Each question counts for 1 po
OleMash [197]

Answer:

0.0004158

0.00041581

Step-by-step explanation:

Given that :

Number of Questions Correct

Probability for Guessing Correctly

0

0.05631351

1

0.18771172

2

0.28156757

3

0.25028229

4

0.14599800

5

0.05839920

6

0.01622200

7

0.00308990

8

0.00038624

9

0.00002861

10

0.00000095

Probability of answering 8 or more questions correctly ;

Direct sum:

P(x ≥ 8) = p(8) + p(9) + p(10)

P(≥ 8) = 0.00038624 + 0.00002861 + 0.00000095

= 0.0004158

Complement :

P(x ≥ 8) = 1 - p(x ≤ 7)

1 - [p(7) + p(6) + p(5) + p(4) + p(3) + p(2) + p(1) + p(0)]

1 - [0.00308990 + 0.01622200 + 0.05839920 + 0.14599800 + 0.25028229 + 0.28156757 + 0.18771172 + 0.05631351]

1 - 0.99958419

= 0.00041581

8 0
3 years ago
Which statements are true? Select all that apply.
xeze [42]

Answer:

A and C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
a bag of a certain type of sand weighs 42 pounds and has a volume of 0.5 cubic feet. a sandbox has a volume of 16 cubic feet. ap
Aleonysh [2.5K]

Answer:

It will take 1344 pounds of sand to fill the sand box.

Step-by-step explanation:

I'm sorry If I got this wrong, have a great day!

8 0
3 years ago
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

8 0
3 years ago
16. Under the Christmas tree at my house, there are five presents for my wife, three presents for me, and 8
Vladimir79 [104]

Answer:

a) 31.25%

b) 50%

c) 18.75%

6 0
3 years ago
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