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3 years ago

4. Find MN help plzzzzz

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

Step-by-step explanation:

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10 x 10 - 4 divided by 7

TEA [102]

Answer:

13.7142857143

Step-by-step explanation:

If you need to round then do so, or i will comment the rounded version if needed.

3 0

3 years ago

What is the slope of a line that is perpendicular to the graph of y = –3x?

Morgarella [4.7K]

Step-by-step explanation:

Hey there!

The equation is; y= -3x

or, 3x+y = 0.......... (I)

From equation (I)

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$m1= \frac{ - 3}{1}$

Therefore, m= -3

Now, As per the condition of perpendicular lines;

M1*M2 = -1

-3*M2 = -1

M2= -1/-3

Therefore, the slope of a line which is perpendicular to the equation is; 1/3.

Hope it helps...

7 0

3 years ago

A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At

Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

The particle starts at rest, so $v(0)=0$ , and we have

$v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t$

Then the position function is

$x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du$

with $x(0)=6$ , so

$x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t$

b. The particle is at rest whenever $v(t)=0$ ; this happens for

$6\sin t=0\implies \sin t=0\implies t=n\pi$

where $n$ is any integer.

3 0

3 years ago

The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with an average weight of 5

Lisa [10]

Answer: 0.4987

Step-by-step explanation:

Given : The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with

Mean : $\mu=5\text { lbs}$

Standard deviation : $\sigma= 2\text{ lbs}$

Let X be the random variable that represents the weight of randomly selected student .

Z score : $z=\dfrac{x-\mu}{\sigma}$

For x = 5 lbs

$z=\dfrac{5-5}{2}=0$

For x = 11 lbs

$z=\dfrac{11-5}{2}=3$

By using the standard normal distribution table , the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs :-

$P(5$

Hence, the probability that the weight of the newborn baby boy will be between 5 lbs and 11 lbs =0.4987

5 0

3 years ago

Give P(-1, 8) and Q(5,12), and MN is the image of PQ under a translation of T

Brilliant_brown [7]

Coordinates of N are (-55, 6)

4 0

3 years ago

4. Find MN help plzzzzz​

4. Find MN help plzzzzz