9x - 2y = 11 ... (i)
5x - 2y = 15 ... (ii)
Subtracting equation (ii) from (i) we get;
4x + 0 = -4
4x=-4 , x = -1
Replacing x = -1 in equation (i) we get;
9(-1) - 2y = 11
-9 - 2y = 11
-2y = 20
y = 20 ÷ -2 = -10
The solution to the system of equations is (-1,-10).
Answer:
b
Step-by-step explanation:
(x - 4) (x - 3)
x^2 - 3x - 4x + 12 (you distribute x in (x-4) to each of the terms x and -3 and multiply them. x*x is x^2 and x*(-3) is -3x. Then, you distribute -4 in (x-4) to each of the terms x and -3 and multiply them. -4*x is -4x and -4*-3 is 12)
x^2 - 7x + 12 (B)
<span>circle area = </span>πr² ⇒
The answer is (D) or 1728 In³
A number(p) plus six
six plus a number(p)
