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Tcecarenko [31]
3 years ago
10

what is the volume of this box if the volume is scaled down to 1/10? the original volume is 528 and the length is 11 inches the

width is 8 inches and the height is 6.​
Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

Step-by-step explanation:

I assume the box is a rectangular figure

Volume, V=L*W*H

V=11*8*6=528 in^3

528*1/10=52.8 in^3

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36A^4+16Y^2<br> Can someone help me
Alenkasestr [34]

Answer:

4(9a^4+4y^2)

Step-by-step explanation:

factor out common term

6 0
3 years ago
Question 12 helllllllppppp plazzzzzzz
Eddi Din [679]

Answer:

Step-by-step explanation:

It says Renita takes minutes to ride half a mile.

She leaves 30 minutes before school.

Total distance is

               2\frac{1}{2} = \frac{1}{2}+ \frac{1}{2} +\frac{1}{2} +\frac{1}{2} +\frac{1}{2}\\

In

2\frac{1}{2} \ there \ are \ 5 \ times  \  \frac{1}{2} \ mile .\\

Therefore total time to reach school will be  5 x 5 = 25minutes.

Since she leaves 30minutes before school. She will reach 5minutes early before school.

8 0
3 years ago
Write the equation of the line with a slope of 24 and a y-intercept of -5​
zmey [24]

Answer:

y=24x-5

Step-by-step explanation:

General slope intercept form equation of straight line is given as

y=mx+b

where m is slope and b is y-intercept

here m=24 and b=-5

Therefore

y=mx+b=24x-5

8 0
3 years ago
Logan made a treasure map he treasure is 25 cm away from his location if each 1 cm on the scale drawing equals 5 m then how far
Doss [256]
Logan is 125 meters away from the treasure.


Also, this question seems like an elementary school question, not a high school question, so why does it say that you are in high school?
8 0
3 years ago
A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag
Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

H_0: p_x =p_y\\H_a: p_x \neq p_y

(Two tailed test at 5% level of significance)

                Group I            Group II              combined p

n                  270                 300                         570

favor            120                  140                          260

p                   0.4444            0.4667                   0.4561

Std error   for differene = \sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209

p difference = -0.0223    

Z statistic = p diff/std error =       -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

        At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

7 0
3 years ago
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