Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
Answer:
The remaining liquid has a volume of 345.4 cm³.
Step-by-step explanation:
To solve this question we first need to calculate the volume of each container.
Cylindrical:
Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³
Cone:
Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³
Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:
remaining liquid = 1099 - 753.6 = 345.4 cm³
Answer:
56 degrees
Step-by-step explanation:
We know that the angle TWR must be 90 degrees because TWK is 90 degrees and the two angles msut add up to 180. Since we know that TWR=90 degrees and since LWR=34 degrees we do 90-34 so angle 2=56 degrees.
Answer:
<h2>D. points A and B</h2>
Step-by-step explanation:
Look at the picture.
