All categories

2 years ago

5 points

Mathematics

1 answer:

azamat2 years ago

3 0

Step-by-step explanation:

it so easy bro 5.5 ok bro.

You might be interested in

Two objects that have the same mass are dropped from the top of a 20 m

mihalych1998 [28]

Answer:

it is the answer that he said

Step-by-step explanation:

6 0

3 years ago

This relation is a function:<br> {(5,-2), (6,-2),(7,-2), (8,-2)}<br> A.True<br> B.False

AlladinOne [14]

Answer:

true

Step-by-step explanation:

each x-value have exactly only one y-value

8 0

3 years ago

I am stuckk on this

shusha [124]

Answer:

192

try photo math

4 0

2 years ago

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

5 0

2 years ago

Determine the area and perimeter

frosja888 [35]

Answer:

Area is the total surface covered by the shape and perimeter is the total length of the shape.

4 0

2 years ago