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3 years ago

6

Is the perimeter of an equilateral triangle proportional to the side length of the triangle?Explain your reasoning.

1 answer:

babunello [35]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

I think so because it's the same on both sides.

I don't know man. I'm not the best at math :)

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Help would really be appreciated. The question is in the picture.

Vikentia [17]

|-11+8|=|-3|=3. Plug in f(-11)

4 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

2 years ago

The formula to convert Fahrenheit to Celsius is C - 5 (F - 32). Convert 30°C to

bulgar [2K]

Answer:

D. *6F

Step-by-step explanation:

C=(F-32)*5/9

30=(F-32)*5/9

F = (30*9)/5+32

F = 86

6 0

3 years ago

Mark did 2/5 of a job and Alan did 1/3 of the remainder. The fraction of the job left undone

Evgesh-ka [11]

2/5=4/10=12/30 1/3=10/30 12/30+10/30=22/30 22/30=11/15

4 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!<br><br> Subract and simplify.

pantera1 [17]

Answer: C

<u>Step-by-step explanation:</u>

$\dfrac{x+1}{x-5} - \dfrac{x-2}{x+3}$

= $\dfrac{x+1}{x-5}(\dfrac{x+3}{x+3}) - \dfrac{x-2}{x+3}(\dfrac{x-5}{x-5})$

= $\dfrac{x^{2}+4x+3}{(x-5)(x+3)} - \dfrac{x^{2}-7x+10}{(x-5)(x+3)}$

= $\dfrac{x^{2}+4x+3-(x^{2}-7x+10)}{(x-5)(x+3)}$

= $\dfrac{11x-7}{(x-5)(x+3)}$

5 0

3 years ago