$\frac{x-2}{x+3} + \frac{10x}{ x^{2} -9}= \\ = \frac{x-2}{x+3}+ \frac{10x}{(x-3)(x+3)}=$
Restrictions are: x ≠ - 3, x ≠ 3.
$= \frac{(x+2)(x-3)+10x}{(x+3)(x-3)}= \\ \frac{ x^{2} -3x+2x-6+10x}{(x+3)(x-3)}= \\ = \frac{ x^{2} +9x-6}{(x+3)(x-3)}$

6 0

3 years ago

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Which of the following trigonometric expressions represents an inverse function?

elena-14-01-66 [18.8K]

Answer:

the second one:

tan-1(xdegree)

Step-by-step explanation:

7 0

3 years ago

What is the center of the data in the dot plot?

rewona [7]

its not 2.5 for sure thats what i know

Step-by-step explanation:

idk

4 0

3 years ago