Answer:
4s¹²/(9t⁴)
Step-by-step explanation:
<u>Solving in steps:</u>
- (3s⁻⁴t⁷s⁰)⁻²(-2s²t⁵)² =
- 3⁻²s⁻⁴ˣ⁻²t⁷ˣ⁻²(-2)²s²ˣ²t⁵ˣ² =
- 1/9×s⁸t⁻¹⁴(4)s⁴t¹⁰ =
- 4/9 ×s⁸⁺⁴t⁻¹⁴⁺¹⁰ =
- 4/9 ×s¹²t⁻⁴=
- 4s¹²/(9t⁴)
There is one solution that the intersecting lines have cause two solution doesn't have the same slope.
You have to simplify the 1/5 first.
Then simplify the square root of 1 to equal 1
Then rationalize the denominator
Then simplify
1) Point A will be at (-4,4)
2) I think an equilateral triangle can't be right triangle