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Contact [7]
3 years ago
9

How do you simplify the square root of 97? I'm finding the distance from points (-4, 3) and (5, -1) and the distance between the

m is the square root of 97. But how do i simplify that, if i make it 9 square root of 16, how do i simplify that further? or is that wrong altogether?
Mathematics
1 answer:
Maru [420]3 years ago
8 0
97 is not a pefect square. You can obtain the square root of 97 using a calculator.
Using a calculator, square root of 97 is approximately 9.85
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Angle A= ? <br> HELP HELP HELP
vazorg [7]

Answer:

A = 41.41

Step-by-step explanation:

Since this is a right angle, we can use trig functions

cos A = adjacent/ hypotenuse

Cos A = 6/8

Taking the inverse cos of each side

cos ^ -1 ( cos A) = cos ^-1 ( 6/8)

A =41.40962211

Rounding to the nearest hundredth

A = 41.41

6 0
2 years ago
What’s the equation of a trapezoid
saul85 [17]
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4 0
3 years ago
What is the measure of each interior angle of a regular decagon (10 sides)?
bixtya [17]
6)a

if we put n as the number of sides in a regular polygon, the formula to find the measure of each angle is
\frac{(n - 2) \times 180}{n}
so the answer will be
\frac{(10 - 2) \times 180 }{10}   = \frac{1440}{10}  = 144
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7 0
3 years ago
Read 2 more answers
find the standard form of equation of a line perpendicular to 4X plus 5Y equals 40 that includes the point -10, -3
snow_tiger [21]

The equation of line in standard form is 5x - 4y = -38

<em><u>Solution:</u></em>

Given that we have to find the equation of line perpendicular to 4x + 5y = 40 that includes the point (-10, -3)

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

4x + 5y = 40

Rearranging to slope intercept form, we get

5y = -4x + 40

y = \frac{-4}{5}x + \frac{40}{5}\\\\y = \frac{-4}{5}x + 8

On comparing the above equation with eqn 1,

m = \frac{-4}{5}

We know that product of slope of line and slope of line perpendicular to given line is equal to -1

Therefore,

\frac{-4}{5} \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{5}{4}

Now find the equation of line with slope 5/4 and passing through (-10, -3)

Substitute m = \frac{5}{4} and (x, y) = (-10, -3) in eqn 1

-3 = \frac{5}{4}(-10) + c\\\\-3 = \frac{-25}{2} + c\\\\c = -3 + \frac{25}{2}\\\\c = \frac{-6 + 25}{2}\\\\c = \frac{19}{2}

Substitute c = \frac{19}{2} and m = \frac{5}{4} in eqn 1

y = \frac{5}{4}x + \frac{19}{2}

The standard form of an equation is Ax + By = C

Therefore,

\frac{5}{4}x - y = -\frac{19}{2}\\\\\frac{5x - 4y}{4} = \frac{-19}{2}\\\\5x - 4y = -38

Thus the equation of line in standard form is found

4 0
3 years ago
If a function has a vertical asymptote at a certain x-value, then the function is _____ at that value.
Dmitriy789 [7]

The denominator of the function would be equal to zero so it would be undefined.

8 0
3 years ago
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