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KIM [24]
3 years ago
8

No solution, one solution, or infinite solutions

Mathematics
1 answer:
aliina [53]3 years ago
4 0
GOD IS GREAT SPREAD THE WORD
You might be interested in
In how many ways can a committee of five women and four men be formed from a group of seven women and seven men?
vekshin1
Number of combinations of 5 women from 7  = 7C5 =  7*6 / 2 = 21
for men its 7C4  = 7*6*5 / 3*2 =  35

Total number of ways = 21*35  = 735
6 0
3 years ago
Explain how to use the distributive property to find an expression that is equivalent to 20 + 16. PLZ REALLY NEED HELP
anzhelika [568]

Answer:

16 + 20 or 2 x 18

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
10(a-2.5+0.56b) is this equivalent to 10a - 25+56b
kirill115 [55]

Hey there!

10(a - 2.5 + 0.56b)

= 10(a) + 10(-2.5) + 10(0.56b)

= 10a - 25 + 5.6b

= 10a + 5.6b - 25

Therefore, your answer is: 10a + 5.6b - 25

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0
3 years ago
A car traveld 32 miles in 4 hours at this rate how many miles will the car travel in 0.5 hours
Mandarinka [93]

Answer:

4 miles

Step-by-step explanation:

In order to find how many miles the car will travel in 0.5 hours, we can set up a proportion.

\frac{32}{4} = \frac{x}{0.5}

We can now cross multiply to find the value of x.

32 \cdot 0.5 = 16\\\\16\div4 = 4

So the car can travel 4 miles in 0.5 hours.

Hope this helped!

5 0
3 years ago
Read 2 more answers
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
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